What is the $"molality"$ of a $4.00g$ mass of sodium chloride dissolved in $100mL$ of water?

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Answer 1 · 2017-09-13T04:57:39

$"Molality"-="Moles of solute"/"Kilograms of solvent"~=0.7*mol*kg^-1$

And so here $"molality"=((4.00*g)/(58.44*g*mol^-1))/(100*gxx10^-3*kg*g^-1)=??*mol*kg^-1$ .

At these concentrations, $"molality"$ would be little different to $"molarity"="Moles of solute"/"Litres of solution"$

What is the "molality""molality" of a 4.00*g4.00*g mass of sodium chloride dissolved in 100*mL100*mL of water?