If $ρ = 3.97 \cdot g \cdot c m^{- 3}$ $rho=3.97gcm^-3$ , what is the mass of an object whose volume is $575 \cdot c m^{3}$ $575*cm^3$ ?

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Answer 1 · 2017-09-15T17:46:15

@coleash711 you have already been given the formula for density....

$ρ = \frac{Mass}{Volume}$ $rho="Mass"/"Volume"$ , and thus $mass = volume \times ρ$ $"mass"="volume"xxrho$

$575 \cdot c m^{3} \times 3.97 \cdot g \cdot c m^{- 3} = over 2 kg of sparkler......$ $575*cm^3xx3.97*g*cm^-3="over 2 kg of sparkler......"$

If ρ=3.97⋅g⋅cm−3rho=3.97*g*cm^-3, what is the mass of an object whose volume is 575⋅cm3575*cm^3?