What is the mass of "22.31 cm"^322.31 cm3 of zinc if the density of this metal is "7.1 g/cm"^37.1 g/cm3 ?
1 Answer
Here's what I got.
Explanation:
The thing to remember about a substance's density is that it tells you the mass of exactly
In this case, you know that the density of zinc is equal to
"7.1 g cm"^(-3) " " implies " " "1 cm"^3color(white)(.)"of zinc has a mass of 7.1 g"7.1 g cm−3 ⇒ 1 cm3.of zinc has a mass of 7.1 g
Now, you know that your sample has a volume of
(xcolor(white)(.)color(red)(cancel(color(black)("g"))))/(22.31 color(red)(cancel(color(black)("cm"^3)))) = (7.1 color(red)(cancel(color(black)("g"))))/(1 color(red)(cancel(color(black)("cm"^3))))
This will get you
x = 22.31 * 7.1 = 158.4
You can thus say that your sample will have a mass of
color(darkgreen)(ul(color(black)("mass = 158.4 g")))
I'll leave the answer rounded to four sig figs, but keep in mind that you have two sig figs for the density of zinc.
