What is the general solution of the differential equation ? dy/dx=y+cdydx=y+c
1 Answer
Nov 21, 2017
y = Be^x - c y=Bex−c
Explanation:
We have:
dy/dx = y + cdydx=y+c
This is a First Order Linear Differential Equation which we can rewrite as a separable equation and thus "separate the variables" to get:
1/(y + c) \ dy/dx = 1
:. int \ 1/(y + c) \ dy = int \ dx
Which consists of standard integral function ; so we can integrate to get
ln|y + c| = x + A
Taking exponentials we get:
|y + c| = e^(x + A)
And as the exponential is positive for all values; we must have:
y + c = e^xe^A
Which we can write as:
y = Be^x - c