Question #4499e

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Question #4499e

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Answer 1 · 2017-12-11T03:07:41

$2916 x^{14} + 3888 x^{11} + 1944 x^{8} + 432 x^{5} + 36 x^{2}$ $2916x^14+3888x^11+1944x^8+432x^5+36x^2$

Explanation:

$\frac{d y}{d x} = {(3 x^{3} + 1)}^{4}$ $dy/dx=(3x^3+1)^4$

let z be $3 x^{3} + 1$ $3x^3+1$

$\frac{d y}{d x} = \frac{d}{d x} (z^{4}) \cdot \frac{d z}{d x}$ $dy/dx=d/dx(z^4)*dz/dx$

$= 4 z^{3} \cdot (9 x^{2})$ $= 4z^3*(9x^2)$
$= 36 {(3 x^{3} + 1)}^{4} \cdot x^{2}$ $= 36(3x^3+1)^4*x^2$
$= 2916 x^{14} + 3888 x^{11} + 1944 x^{8} + 432 x^{5} + 36 x^{2}$ $=2916x^14+3888x^11+1944x^8+432x^5+36x^2$

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Question #4499e

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