Question #583b0

1 Answer
Jack L. · Stefan V.
Jan 28, 2018

1.429 g/L

Explanation:

We know that one mole of any substance at STP will occupy a volume of 22.422.4 liters. We know that oxygen is diatomic, therefore one mole of oxygen weights "32 g"32 g.

Apply the density formula:

rho =m/Vρ=mV

rho =("32 g O"_2) /("22.4 L")ρ=32 g O222.4 L

You get

rho = "1.42857 g/L"ρ=1.42857 g/L

you round it up to "1.429 g/L"1.429 g/L.

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