Question

A ball rolling down a hill at 4.0 m/s accelerates at 2.0 m/s2. What is its velocity 5.0s later?

Answer 1

`14.0" ms"^-1`

Explanation:

We need to use the kinematic equation involving quantities of interest: initial velocity `u`, final velocity `v`, acceleration `a` and time `t`

`v=u+at`

Inserting given quantities
`v=4.0+2.0xx5.0`
`=>v=14.0" ms"^-1`