A body moves with uniform acceleration a and zero initial velocity. another body B starts from the same point and moves in same direction with constant velocity v. the two bodies meet after a time t. the value of t is ?

Question

options:-
1. 2v/a
2. v/a
3. v/2a
4. #sqrt(v/(2a))#

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Answer 1 · 2017-08-05T13:55:20

The answer is option #(1)#, i.e #=(2v)/a#

We apply the equation of motion to the body #A#

#s=ut+1/2at^2#

The initial velocity of #A# is #u_A=0#

The aceleration is #a_A=a#

So, the distance after the time #t# i

#s=0+1/2at^2#

We apply the equation of motion to the body #B#

#s=vt#

Therefore,

#vt=1/2at^2#

#t=(2v)/a#