A body moves with uniform acceleration a and zero initial velocity. another body B starts from the same point and moves in same direction with constant velocity v. the two bodies meet after a time t. the value of t is ?

Question

options:-
1. 2v/a
2. v/a
3. v/2a
4. $sqrt(v/(2a))$

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Answer 1 · 2017-08-05T13:55:20

The answer is option $(1)$ , i.e $=(2v)/a$

We apply the equation of motion to the body $A$

$s=ut+1/2at^2$

The initial velocity of $A$ is $u_A=0$

The aceleration is $a_A=a$

So, the distance after the time $t$ i

$s=0+1/2at^2$

We apply the equation of motion to the body $B$

$s=vt$

Therefore,

$vt=1/2at^2$

$t=(2v)/a$