A mass of 1 kg is thrown up with velocity of 100 m/s. After 5 second it explodes into 2 parts. One part of mass 400 g move down with a velocity 25 m/s. Calculate the velocity of other part just after explosion?? (g=10 m/s²)

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A mass of 1 kg is thrown up with velocity of 100 m/s. After 5 second it explodes into 2 parts. One part of mass 400 g move down with a velocity 25 m/s. Calculate the velocity of other part just after explosion?? (g=10 m/s²)

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Answer 1 · 2018-03-09T19:07:17

After $5 s$ $5s$ of throwing the whole mass will have a velocity of $v = 100 - (10 \times 5) = 50 m s^{- 1}$ $v=100-(10×5)=50 ms^-1$ (using , $v = u - g t$ $v=u-g t$ )

Now,let the other mass will move with velocity $v$ $v$

So,considering upward velocity to be positive,we can say momentum after the explosion will be,

$(\frac{400}{1000} \times (- 25) + \frac{600}{1000} \times v) K g m s^{- 1}$ $(400/1000 ×(-25) + 600/1000 ×v) Kg ms^-1$

And,momentum before the collision was $1 \times 50 K g m s^{- 1}$ $1×50 Kg ms^-1$

Now,applying law of conservation of momentum we get,

$1 \times 50 = - 0.4 \times 25 + 0.6 \times v$ $1×50=-0.4×25 +0.6×v$

Or, $v = 100 m s^{- 1}$ $v=100 ms^-1$

So,the other mass will go upwards with a velocity of $100 m s^{- 1}$ $100 ms^-1$

Note here we considered that for a time being external force gravity had no effect on the motion of the two objects,so we did apply the law of conservation of momentum.

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A mass of 1 kg is thrown up with velocity of 100 m/s. After 5 second it explodes into 2 parts. One part of mass 400 g move down with a velocity 25 m/s. Calculate the velocity of other part just after explosion?? (g=10 m/s²)

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