Question

A noble gas is placed in a 10.0 liter container. The noble gas has a mass of 25.25 g, the pressure is 3.05 atm, and the temperature is 24°C. Find the molar mass and symbol for the gas. ?

Answer 1

I makes it.....`"neon gas, Ne.........."`

Explanation:

We work out the molar mass of the gas...`PV=nRT` `=` `"mass of gas"/"molar mass of gas"xx0.0821*(L*atm)/(K*mol)xx297.15*K.`

And so....`"molar mass of gas"="mass of gas"/(PxxV)xx0.0821*(L*atm)/(K*mol)xx297.15*K`

`=(25.25*g)/(3.05*cancel(atm)xx10.0*cancelL)xx0.0821*cancel(L*atm)/(cancelK*mol)xx297.15*cancelK`

`=20.2*g*mol^-1`

And this molecular mass is precisely consistent with that of neon gas.... I hope the question drew on actual data....the fit makes me suspicious.....