Question

a) What is the acceleration of the blocks? b) What is the net force on each block? c) What is the tension in the string?

A pulley with a string has 58 kg on one end and 95kg at the other.

Answer 1

see below

Explanation:

From the second dynamic equation
`F= ma`
and knowing that the total force is the difference of the two forces, while the mass is the sum, you have the aceleration
`a= F/m= ((95-58) kg xx 9,8 m/s^2)/((95+58)kg)=2.4 m/s^2`=
On the block that is going down there is a net force given by the gravity force less the inerzial force
`F= 95 kg xx (9,8-2,4) m/s^2=7.0 xx 10^2 N`
On the block that is going up there is a net force given by the inertial force plus the gravity force
`F= 58 kg xx (9,8 +2,4) m/s^2=7.0 xx 10^2 N`
the tension in the string is the sum
`T=14 xx 10^2 N`

Answer 2

`a.)` acceleration of both the blocks =`2.37 ms^-2`

`b.)` net force on `58 Kg` is `137.46N` acting upwards,and net force on `95 Kg` is `225.15N` acting downwards.

`c.)` tension in the string is `705.86 N`

Please see images below,

Explanation: