a) What is the acceleration of the blocks? b) What is the net force on each block? c) What is the tension in the string?

A pulley with a string has 58 kg on one end and 95kg at the other.

2 Answers
Mar 12, 2018

see below

Explanation:

From the second dynamic equation
F= maF=ma
and knowing that the total force is the difference of the two forces, while the mass is the sum, you have the aceleration
a= F/m= ((95-58) kg xx 9,8 m/s^2)/((95+58)kg)=2.4 m/s^2a=Fm=(9558)kg×9,8ms2(95+58)kg=2.4ms2=
On the block that is going down there is a net force given by the gravity force less the inerzial force
F= 95 kg xx (9,8-2,4) m/s^2=7.0 xx 10^2 NF=95kg×(9,82,4)ms2=7.0×102N
On the block that is going up there is a net force given by the inertial force plus the gravity force
F= 58 kg xx (9,8 +2,4) m/s^2=7.0 xx 10^2 NF=58kg×(9,8+2,4)ms2=7.0×102N
the tension in the string is the sum
T=14 xx 10^2 N T=14×102N

Mar 12, 2018

a.) a.) acceleration of both the blocks =2.37 ms^-22.37ms2

b.)b.) net force on 58 Kg58Kg is 137.46N137.46N acting upwards,and net force on 95 Kg95Kg is 225.15N225.15N acting downwards.

c.)c.) tension in the string is 705.86 N705.86N

Please see images below,

Explanation:

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