A worker pushes a wheelbarrow with a force 40N over a level distance 6m. Frictional force 24N acts on the wheelbarrow in opposite direction to that of the worker, find the net work done on wheelbarrow?

1 Answer
Gió
Aug 6, 2015

I found: W=96J

Explanation:

Considering the situation:
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The net force will be:
F_("net")=DeltaF=F_1-f=40-24=16N
the work done will then be:
W=F_("net")*s=16*6=96J

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