Question

An experiment calls for 5.50 L of sulfur dioxide at 0°C and 1.00 atm. What would the volume of this gas be at 30°C if the pressure remains constant?

Answer 1

You don’t need to use 1.00 atm when you have `0^@ "C"` since you also have `30^@ "C"`. It’s there to throw you off guard. Use Charles' Law, `V_1/T_1 = V_2/T_2`.

Explanation:

`V_1 = "5.50 L"`
`T_1 = 0^@ "C" + 273 = "273 K"`
`T_2= 30^@ "C" + 273 = "303 K"`

`(("5.50 L")("303 K")) / "273 K" = V_2 = "6.10 L"`