An object with a mass of $2 kg$ is moving at $5 m/s$ over a surface with a kinetic friction coefficient of $3$ . How much power will it take to accelerate the object at #3 m/s^2?

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Answer 1 · 2017-04-07T09:58:52

The power is $=324W$

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The frictional force is

$F_r=mu_k*N$

The normal force is $N=mg$

So,

$F_r=mu_k*mg$

Resolving in the horizontal direction $rarr^+$

$F-F_r=ma$

So,

$F=F_r+ma$

$F=mu_kmg+ma$

$=m(mu_kg+a)$

$=2(3*9.8+3)$

$=2*32.4=64.8N$

The power needed is

$P=F*v=64.8*5=324W$

An object with a mass of 2 kg2 kg is moving at 5 m/s5 m/s over a surface with a kinetic friction coefficient of 3 3 . How much power will it take to accelerate the object at #3 m/s^2?