Angela math test scores so far are as follows: 87, 96, 82, 77. What score must Angela make on the final test in order to have a test average of 88?

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Answer 1 · 2015-09-16T00:14:20

Let $x$ be the score of the final test then

$(87+96+82+77+x)/5=88=>x=98$

Answer 2 · 2015-09-16T00:15:58

I found $98$

Considering an average of $n$ scores:

$(Sigma"scores")/n=(87+96+82+77+x)/5=88$
you get:
$342+x=5xx88$
$x=440-342=98$

Answer 3 · 2015-09-16T00:18:04

Angela must score 98 in her final test.

Let $x$ represent the score that Angela gets on her final test.

The average of all 5 of the tests can be found by computing,

$bar x=(87+96+82+77+x)/5=88$

from this we just use algebra and solve for $x$ .

$(342+x)/5=88$
$x=(88xx5)-342$
$x=98$

Hope it helps :)