Anyone knows the derivative of [ln(sec x tan x)^2]^2 ?

1 Answer
Sonnhard
Jun 9, 2018

4ln(sec(x)tan(x))^2*ln(sec(x)*tan(x))*(sec(x)^3+sec(x)*tan(x))4ln(sec(x)tan(x))2⋅ln(sec(x)⋅tan(x))⋅(sec(x)3+sec(x)⋅tan(x))

Explanation:

Using the chain and the power rule and that
(sec(x)*tan(x))'=sec(x)^3+sec(x)tan(x)
so we get

2ln(sec(x)tan(x))^2*2ln(sec(x)tan(x))*(sec(x)^3+sec(x)*tan(x))

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