Can I get one more help please? Thank you!

The velocity of sound in air is given by the equation v=20sqrt(273+t)v=20273+t , where vv is the velocity in meters per second and tt is the temperature in degrees Celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree. Show your work

1 Answer
Sep 15, 2017

Per given information the equation governing velocity vv of sound at t^@CtC is

v=20(273+t)^(1/2) v=20(273+t)12

Plotting the equation using inbuilt graphing tool xx-axis representing temperature and yy-axis representing velocity in ms^-1ms1 we get the following graph.

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We are to find temperature at which v=329ms^-1v=329ms1.

Expanding the graph at the point of interest as below:

graph{y=20*(273+x)^(1/2) [-2.8, -2, 328, 330]}

We see that v=329ms^-1v=329ms1 at t=-2.4^@Ct=2.4C

t=-2^@Ct=2C, rounded to nearest degree.