Can someone help me simplify this please? #(x^2-y^2)/y^2 xx y^3/(y-x)#
1 Answer
Apr 30, 2018
Explanation:
#x^2-y^2" is a "color(blue)"difference of squares"#
#"and factors in general as"#
#•color(white)(x)a^2-b^2=(a-b)(a+b)#
#rArrx^2-y^2=(x-y)(x+y)#
#rArr((x-y)(x+y))/y^2xxy^3/(y-x)#
#"factor out "-1" from "y-x#
#rArry-x=-(x-y)#
#rArr(cancel((x-y))(x+y))/cancel(y^2)xx(cancel(y^2)y)/-cancel((x-y))#
#=-y(x+y)#
