Can someone please help me, write a quadratic equation with roots -3 and 4 in standard form?

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Can someone please help me, write a quadratic equation with roots -3 and 4 in standard form?

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Answer 1 · 2018-03-06T18:07:32

In standard form it is
$x^{2} + x - 12$ $x^2+x-12$

Explanation:

roots are $- 3, 4$ $-3,4$
standard form is
$x^{2} - (sum of the roots) x + product of roots$ $x^2-"(sum of the roots)"x+"product of roots"$
Here,
$(sum of the roots) = - 3 + 4 = 1$ $"(sum of the roots)"=-3+4=1$
$product of roots = - 3 \times 4 = - 12$ $"product of roots"=-3xx4=-12$
Substituting
$x^{2} - (sum of the roots) x + product of roots = x^{2} + 1 x + (- 12)$ $x^2-"(sum of the roots)"x+"product of roots"=x^2+1x+(-12)$
In standard form it is
$x^{2} + x - 12$ $x^2+x-12$

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Can someone please help me, write a quadratic equation with roots -3 and 4 in standard form?

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