Can the logarithm of a number be negative? Can it be imaginary?

1 Answer
Oct 31, 2015

Yes and yes, but it gets complicated...

Explanation:

e^x:RR->(0,oo) is a one to one Real-valued function with inverse ln:(0,oo)->RR

If 0 < x < 1 then ln x < 0

e^z:CC->CC \ {0} is a many to one Complex-valued function. As a result, it has no inverse function. However, it is possible to extend the definition of logs to Complex numbers. We can limit the domain of e^z to make it a one to one function, allowing the definition of an inverse "ln z".

For example,

e^z:{a+ib in CC : -pi < b <= pi} -> CC \ {0} is a one one function.

If we use this definition then

ln z:CC \ {0} -> {a+ib in CC : -pi < b <= pi}

is well defined and we find values like ln(-1) = i pi