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Answer 1 · 2017-12-04T07:03:42

#80.41, 279.59# Degrees

.

#sec^2x-6secx=0#

#secx(secx-6)=0#

#secx=0#, or #1/cosx=0#. This answer is not valid because it it means that #cosx=oo#. #cos# values can only be between #+-1#.

#secx-6=0#
#secx=6#, or #1/cosx=6#

#cosx=1/6#

#x=arccos(1/6)=80.41# Degrees

#x=360-80.41=279.59# Degrees