Question

Consider this quadratic function `f(x)=2x^2-8x+1`, how do you find the axis of symmetry?

Answer 1

The equation of the axis of symmetry for `f(x) = 2x ^2 - 8x + 1` is `x = 2`.

Explanation:

This quadratic function is in standard form, `f(x) = ax^2 + bx + c`.
For every quadratic function in standard form the axis of symmetry is given by the formula `x = (-b)/(2a)`.

In `f(x) = 2x^2 - 8x + 1`, `a = 2`, `b = -8`, and `c = 1`. So, the equation for the axis of symmetry is given by

`x = (-(-8))/(2*2)`

`x = 8/4`

`x = 2`