Cot B + cos B divided by sec B - cos B = csc B + 1 divided by tan^2 B can it be verified?

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Answer 1 · 2018-03-13T04:26:54

Yes... see below

$(Cot B + cos B)/(sec B - cos B) = (csc B + 1)/ tan^2 B$

$(CotB+cosB)/(1/cosB - cos^2 B/cosB)=$

$(CosB/SinB+(cosBsinB)/sinB)/(sin^2B/cosB)=$

$((CosB+cosBsinB)/sinB)*(cosB)/(sin^2B)=$

$((Cos^2B+cos^2BsinB)/sin^3B)=$

$Cos^2B/sin^3B+(cos^2BsinB)/sin^3B=$

$Cos^2B/sin^2B*1/sinB+cos^2B/sin^2B=$

$cot^2B*cscB+cot^2B=$

$cscB/tan^2B+1/tan^2B=$

$(cscB+1)/tan^2B$