3.00 moles of gas are in a container with a volume of 60.0 liters and at a temperature of 400. K What is the pressure inside the container?

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3.00 moles of gas are in a container with a volume of 60.0 liters and at a temperature of 400. K What is the pressure inside the container?

Did I do this right?

P $\times$ $xx$ 60 = 3 $\times$ $xx$ 0.0821 $\times$ $xx$ 400
P $\times$ $xx$ 60 = 98.52
P = 0.61

If i did it wrong, can you tell me what i need to improve on? I also have another question. When i get to the last step where i need to divide, which number do i divide with? The number with the unknown variable?

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Answer 1 · 2018-03-06T21:00:45

The pressure of the gas is 1.64 atmospheres.

Explanation:

To solve this problem, we need to use the ideal gas law:

$P V = n R T$ $PV=nRT$

$P$ $P$ is pressure in atmospheres, $V$ $V$ is volume in liters, $n$ $n$ is moles, $R$ $R$ is the universal gas constant, and $T$ $T$ is the temperature in Kelvins.

Plug the known values into the equation and solve for the pressure.

$(P) (60.0) = (3.00) (0.08206) (400)$ $(P)(60.0)=(3.00)(0.08206)(400)$

$P = \frac{(3.00) (0.08206) (400)}{60.0} = 1.64$ $P=((3.00)(0.08206)(400))/(60.0)=1.64$ atm

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3.00 moles of gas are in a container with a volume of 60.0 liters and at a temperature of 400. K What is the pressure inside the container?

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Explanation:

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