Differentiate # y = 9/(2x + 3#?

1 Answer
Jim G.
May 8, 2018

#dy/dx=-18/(2x+3)^2#

Explanation:

#"differentiate using the "color(blue)"chain rule"#

#"given "y=f(g(x))" then"#

#dy/dx=f'(g(x))xxg'(x)#

#"here "y=9/(2x+3)=9(2x+3)^-1#

#rArrdy/dx=-9(2x+3)^-2xxd/dx(2x+3)#

#color(white)(rArrdy/dx)=-9(2x+3)^-2xx2#

#color(white)(rArrdy/dx)=-18/(2x+3)^2#

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