Does the answer to #(log_b5)(log_5b)# depend on the value of b? (a). Yes (b). No (c). Not enough information to answer

1 Answer
Sep 26, 2017

The answer is #b#

Explanation:

If we use #log_a n = loga/logn#, we get:

#((log5)/logb)(logb/log5)#

We can immediately see that this equals #1# IF #b > 0#.

So I make the assumption that #b# is a positive real number.

Hopefully this helps!