Does the answer to #(log_b5)(log_5b)# depend on the value of b? (a). Yes (b). No (c). Not enough information to answer
1 Answer
Sep 26, 2017
The answer is
Explanation:
If we use
#((log5)/logb)(logb/log5)#
We can immediately see that this equals
So I make the assumption that
Hopefully this helps!