Domain of $f(x)=ln((x+1))/x$ ?

Question

1278 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-04T11:53:46

${x in RR : -1 <= x , x !=0}$

$x$ is restricted in $ln(x+1)$ . Since $ln(x)$ is only defined for $x>=0$

$x+1>=0$

But for the denominator $x>0$ and $x<0$

So domain is:

${x in RR : -1 <= x , x !=0}$

Domain of f(x)=ln((x+1))/xf(x)=ln((x+1))/x ?