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Express as a function of a positive acute angle:? cos 240 sin(-110)

1 Answer

Vinícius Ferraz

May 18, 2018

And their product is $+ {cos 60}^{0} \cdot {sin 70}^{0}$ $+ cos 60^0 * sin 70^0$

Explanation:

${cos 240}^{0} = {cos (360 - 240)}^{0} = {cos 120}^{0}$ $cos 240^0 = cos (360 - 240)^0 = cos 120^0$

$= - {cos (180 - 120)}^{0} = - {cos 60}^{0}$ $= - cos(180 - 120)^0 = - cos 60^0$

$sin (- 110^{0}) = - {sin 110}^{0} = - {sin (180 - 110)}^{0}$ $sin (-110^0) = - sin 110^0 = - sin (180 - 110)^0$

$= - {sin 70}^{0}$ $= - sin 70^0$

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