Factored completely, the expression $6 x - x^{3} - x^{2}$ $6x-x^3-x^2$ is equivalent to?

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Answer 1 · 2016-12-15T18:37:18

$- x (x + 3) (x - 2)$ $-x(x + 3)(x - 2)$

First of all, this can be factored as $- x (x^{2} + x - 6)$ $-x(x^2 + x - 6)$ .

Next, we can factor as $- x (x + 3) (x - 2)$ $-x(x + 3)(x - 2)$ .

Hopefully this helps!

Factored completely, the expression 6x−x3−x26x-x^3-x^2 is equivalent to?