Question

Fe2O3(s)+3CO(g)⟶2Fe(s)+3CO2(g) How many moles of Fe2O3 are necessary to produce 1.648 mol of CO2?

Answer 1

You have the stoichiometric equation...

Explanation:

`Fe_2O_3(s) + 3CO stackrel(Delta)rarr2Fe(s) +3CO_2(g)`

And to produce `1.648*mol` `CO_2` you need a THIRD of an equiv of `"ferric oxide"`...a mass of `1.648*molxx1/3xx159.69*g*mol^-1=` `"approx. 90 g"`...