Find $\frac{d y}{d x}$ $dy/dx$ for $ln (e^{x})$ $ln(e^x)$ ?

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Answer 1 · 2017-03-16T07:56:40

You can simplify this before taking the derivative.

${ln e}^{x} = x$ $lne^x = x$

since $ln = {log}_{e}$ $ln = log_e$ . Thus,

$\frac{d y}{d x} = \frac{d}{d x} [x] = 1$ $(dy)/(dx) = d/(dx)[x] = color(blue)(1)$ .

Find dy/dxdydxdy/dx for ln(e^x)ln(ex)ln(e^x)?