Find f"(x) given that 3x²+y²=2 using implicit differentiation?

1 Answer
Aug 17, 2015

f''(x) = -(3(3x^2+y^2))/y^3

Explanation:

3x^2 + y^2 = 2
Differentiate with respect to x:
6x + 2y(dy)/dx = 0
Differentiate once more with respect to x:
6 + 2y(d^2y)/dx^2 + 2(dy/dx)^2 = 0

Re-arrange:
(d^2y)/dx^2 = -(3(3x^2+y^2))/y^3