Find the area of a rectangle that has a length of 2x+3 and width of x. Some one painted an area inside the rectangle that has a length of 3 and a width of x-2. Find the area that was NOT painted.?

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Find the area of a rectangle that has a length of 2x+3 and width of x. Some one painted an area inside the rectangle that has a length of 3 and a width of x-2. Find the area that was NOT painted.?

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Answer 1 · 2018-04-21T03:58:01

$Area of NOT painted portion = 2 x^{2} + 6 = 2 \cdot (x^{2} + 3)$ $color(orange)("Area of NOT painted portion " = color(brown)(2x^2 + 6 = 2 * (x^2 + 3)$

Explanation:

$Area of bigger rectangle A B C D = (2 x + 3) \cdot x = 2 x^{2} + 3 x$ $"Area of bigger rectangle " ABCD = (2x + 3) * x = 2x^2 + 3x$

$Area of painted rectangle E F G H = 3 \cdot (x - 2) = 3 x - 6$ $"Area of painted rectangle " EFGH = 3 * (x - 2) = 3x - 6$

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$Area of NOT painted portion = A r e a A B C D - A r e a E F G H$ $"Area of NOT painted portion "= Area ABCD - Area EFGH$

$Area of NOT painted portion = 2 x^{2} + 3 x - 3 \cdot (x - 2) = 2 x^{2} + 6 = 2 \cdot (x^{2} + 3)$ $"Area of NOT painted portion " = 2x^2 + 3x - 3 * (x - 2) = 2x^2 + 6 = 2 * (x^2 + 3)$

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Find the area of a rectangle that has a length of 2x+3 and width of x. Some one painted an area inside the rectangle that has a length of 3 and a width of x-2. Find the area that was NOT painted.?

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Explanation:

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