Find the discriminant of the quadratic equation -12x^2 + 5x + 2 = 0 ?

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Answer 1 · 2018-02-28T19:54:27

$11$ $11$

The discriminant of a quadratic equation in the form

$a x^{2} + b x + c$ $ax^2+bx+c$

is given by

$\sqrt{b^{2} - 4 a c}$ $sqrt(b^2-4ac)$

For $- 12 x^{2} + 5 x + 2,$ $-12x^2+5x+2,$ we see $a = - 12, b = 5, c = 2$ $a=-12,b=5,c=2$

Plugging in into $\sqrt{b^{2} - 4 a c}$ $sqrt(b^2-4ac)$ , we get

$\sqrt{5^{2} - (4) (2) (- 12)} = \sqrt{25 + 96} = \sqrt{121}$ $sqrt(5^2-(4)(2)(-12))=sqrt(25+96)=sqrt(121)$

$\sqrt{121} = 11$ $sqrt(121)=11$