Find the discriminant of the quadratic equation -12x^2 + 5x + 2 = 0 ?

1 Answer
Feb 28, 2018

1111

Explanation:

The discriminant of a quadratic equation in the form

ax^2+bx+cax2+bx+c

is given by

sqrt(b^2-4ac)b24ac

For -12x^2+5x+2,12x2+5x+2, we see a=-12,b=5,c=2a=12,b=5,c=2

Plugging in into sqrt(b^2-4ac)b24ac, we get

sqrt(5^2-(4)(2)(-12))=sqrt(25+96)=sqrt(121)52(4)(2)(12)=25+96=121

sqrt(121)=11121=11