Find the limit #(x^2-4)/(x^2-7x+12)# as #x# tends to -4. ?
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"How do I solve #y'' + y = -2 sin(x)# with the initial conditions #y(0) = 0# and #y'(0) = 1#?"
1 Answer
Jul 20, 2018
Explanation:
#"the limit can be evaluated using direct substitution"#
#lim_(xto-4)(x^2-4)/(x^2-7x+12)#
#=((-4)^2-4)/((-4)^2-7(-4)+12)#
#=(16-4)/(16+28+12)=12/56=3/14#
