Question

Find the Maclaurin series for F(x)= ∫(e^t -1)/t dt (lower bound=0, upper bound=x) ?

Answer 1

Don't think you can.

Explanation:

`F(x)= int_0^x (e^t - 1)/t \ dt qquad F(0) = 0`

Using Liebnitz rule: `F'(x) = (e^x - 1)/x qquad F'(0) = 0/0`. The limit is 1 but I think you have to stop there.