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${(a - 9)}^{2}$ $(a-9)^2$

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Answer 1 · 2018-03-21T20:39:03

$a^{2} - 18 a + 81$ $a^2-18a+81$

Explanation:

${(a - 9)}^{2} = (a - 9) (a - 9)$ $(a-9)^2=(a-9)(a-9)$

$each term in the second factor is multiplied by each$ $"each term in the second factor is multiplied by each"$
$term in the first factor$ $"term in the first factor"$

$\Rightarrow (a - 9) (a - 9)$ $rArr(color(red)(a-9))(a-9)$

$= a (a - 9) - 9 (a - 9) \leftarrow distribute$ $=color(red)(a)(a-9)color(red)(-9)(a-9)larrcolor(blue)"distribute"$

$= (a \times a) + (a \times - 9) + (- 9 \times a) + (- 9 \times - 9)$ $=(color(red)(a)xxa)+(color(red)(a)xx-9)+(color(red)(-9)xxa)+(color(red)(-9)xx-9)$

$= a^{2} - 9 a - 9 a + 81 \leftarrow collect like terms$ $=a^2-9a-9a+81larrcolor(blue)"collect like terms"$

$= a^{2} - 18 a + 81$ $=a^2-18a+81$

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Find the product?

${(a - 9)}^{2}$ $(a-9)^2$

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${(a - 9)}^{2}$ $(a-9)^2$