Question

For a first order reaction the value of rate constant for the reaction `A(g) -> 2B(g) + C(s)`?

Answer 1

`"Rate = k[A]"`

Explanation:

`A_((g)) -> 2B_((g)) + C_((s))`

From Rate Law, Rate of the above reaction is expressed as

`"Rate" = k[A]^x`

It’s first order reaction so, `x = 1`

`"Rate" = k[A]`

Why is Rate Law important?