Question

For the curve `y=x-x^2`, how do you find the slope of the tangent line to the curve at (1,0)?

Answer 1

First you evaluate the derivative of your function `y'(x)`:
Then you evaluate the derivative at `x=1`, or `y'(1)`, which is the slope of your tangent line.
Try by yourself and if it doesn' work look below for the maths:
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Solution:
`y'(x)=1-2x`
`y'(1)=1-2=-1`