Given #cotphi=-3, sinphi=sqrt10/10# to find the remaining trigonometric function?

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Answer 1 · 2017-03-05T19:28:11

See explanation.

Using the equality:

#tanphi*cot phi =1#

we get that: #cotphi=-1/3#

To calculate #cos phi# we can use the equality:

#cos phi/(sqrt(10)/10)=-3#

From this we know that:

#cos phi=(-3sqrt(10))/10#

Finally we can write the 4 values:

#{(sin phi=sqrt(10)/10),(cos phi=(-3sqrt(10))/10), (tan phi = -3), (cot phi = -1/3) :}#