Question

Given `f(x)=1/8x-3` and `g(x)=x^3`, how do you find `(g^-1of^-1)(-3)`?

Answer 1

zero

Explanation:

`g^-1(x) = root[3]x`

`x = 1/8y - 3 => (x + 3)*8 = f^-1(x)`

`f^-1(-3) = 0`

`g^-1(0) = 0`