Given $f(x)=1/8x-3$ and $g(x)=x^3$ , how do you find $(g^-1og^-1)(-4)$ ?

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Answer 1 · 2017-02-25T14:17:27

$-root(9) 4$

What is the inverse of $g$ ?

$g(x) = y => x = g^-1(y)$

$x^3 = y ==> x = root(3) y => g^-1(x) = root(3) x$

$g^-1(-4) = root(3) {-4}$

$g^-1(g^-1(-4)) = g^-1(root(3) {-4}) = root(3) {root(3) {-4}}$

Given f(x)=1/8x-3f(x)=1/8x-3 and g(x)=x^3g(x)=x^3, how do you find (g^-1og^-1)(-4)(g^-1og^-1)(-4)?