Given $f (x) = | 2 x + 1 |$ $f(x) = |2x + 1|$ , $g(x) = 3x³ -1$ how do you find f(g(x))?

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Answer 1 · 2015-12-17T19:55:06

$f@g(x) = abs(2(3x^3 - 1) + 1)=abs(6x^3-1)$

Keep in mind that $(f@g)(x)$ = $f(g(x))$ so you just have to replace the $x$ in $f$ by the expression of $g$ .

Given f(x) = |2x + 1|f(x)=|2x+1|f(x) = |2x + 1|, g(x) = 3x³ -1g(x) = 3x³ -1 how do you find f(g(x))?