Given $f(x)=2x^2+11x-21$ and $g(x)=2x-3$ how do you determine $y=f(g(x))$ ?

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Answer 1 · 2018-04-30T17:50:55

= $8x^2 -2x - 36$

$f(x) = 2x^2 + 11X -21$
$g(x) = 2x - 3$

Substitute the value of $g(x)$ into the $f(x)$ function .
$f(g(x)) = 2(2x -3)^2 +11(2x - 3) -21$

= $2( 4x^2 -12x + 9) + (22x - 33) -21$

= $( 8x^2 -24x + 18) + (22x - 33) -21$

= $8x^2 -24x + 22x - 33 -21+ 18$

= $8x^2 -2x - 36$

Given f(x)=2x^2+11x-21f(x)=2x^2+11x-21 and g(x)=2x-3g(x)=2x-3 how do you determine y=f(g(x))y=f(g(x))?