Given $f (x) = \sqrt{x + 8}$ $f(x)= sqrt (x+8)$ and $g (x) = 4 x + 1$ $g(x)= 4x + 1$ how do you find f(g(x)) and g(f(x))?

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Answer 1 · 2016-05-01T05:47:31

$f (g (x)) = \sqrt{4 x + 9}$ $f(g(x))=sqrt(4x+9)$ and $g (f (x)) = 4 \sqrt{x + 8} + 1$ $g(f(x))=4sqrt(x+8)+1$

$f (x) = \sqrt{x + 8}$ $f(x)=sqrt(x+8)$ and $g (x) = 4 x + 1$ $g(x)=4x+1$

Hence $f (g (x)) = f (4 x + 1) = \sqrt{(4 x + 1) + 8 = \sqrt{4 x + 9}}$ $f(g(x))=f(4x+1)=sqrt((4x+1)+8=sqrt(4x+9)$

and $g (f (x)) = g (\sqrt{x + 8}) = 4 \sqrt{x + 8} + 1$ $g(f(x))=g(sqrt(x+8))=4sqrt(x+8)+1$

Given f(x)=√x+8f(x)= sqrt (x+8) and g(x)=4x+1g(x)= 4x + 1 how do you find f(g(x)) and g(f(x))?