Given #sectheta>0# and #cottheta<0#, which quadrant does #theta# lie? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Ratnaker Mehta Jan 7, 2017 #theta# lies in the Fourth Quadrant. Explanation: #sec theta > 0 rArr theta in Q_I uu Q_(IV)# #cot theta < 0 rArr theta in Q_(II) uu Q_(IV)# #:. sec theta gt 0 & cottheta lt 0 # #rArr theta in [Q_I uu Q_(IV)] nn [Q_(II) uu Q_(IV)]# But #[AuuB]nn[CuuB]=[AnnC]uuB# #:. theta in [Q_InnQ_(II)]uuQ_(IV)=Q_(IV)# Hence, #theta# lies in the Fourth Quadrant. Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 15795 views around the world You can reuse this answer Creative Commons License