Help on Gas Laws (Combined Gas Law)?

Question

Help on Gas Laws (Combined Gas Law)?

The volume of a gas filled balloon is 30.0 L at 40 degrees Celsius and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure (STP)?

1 Answer

Impact of this question

8965 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-02T18:19:03

Well, $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$ .........

Explanation:

And so we solve for $V_{2}$ $V_2$ ...

$V_{2} = \frac{P_{1} \times V_{1} \times T_{2}}{P_{2} \times T_{1}}$ $V_2=(P_1xxV_1xxT_2)/(P_2xxT_1)$ ...and we fills in the blanks...

$= \frac{153 \cdot k P a \times 30.0 \cdot L \times 273.15 \cdot K}{100 \cdot k P a \times 313.15 \cdot K} = 40.0 \cdot L$ $=(153*kPaxx30.0*Lxx273.15*K)/(100*kPaxx313.15*K)=40.0*L$

Science

Math

Humanities

... and beyond

Help on Gas Laws (Combined Gas Law)?

The volume of a gas filled balloon is 30.0 L at 40 degrees Celsius and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure (STP)?

1 Answer

Explanation:

Related questions

Impact of this question