Help please? Integral question below. Don’t really understand the concept of integrals in general. Thanks!

enter image source here

1 Answer
Dec 8, 2017

This is a question involving the Fundamental Theorem of Calculus.

Explanation:

For g(y) = int_3^y f(x) dx, FTC part 1 gives us

g'(y) = f(y)

Now we want g''(y) = f'(y) where f(y) = int_0^siny sqrt(1+t^2) dt

Again, using FTC part 1, this time with the chain rule as well, we get:

g''(y) = f'(y) = sqrt(1+sin^2y) * d/dy(siny)

= sqrt(1+sin^2y) cosy

At y=pi/6, we get

g''(pi/6) = sqrt(1+sin^2(pi/6)) cos(pi/6)

= sqrt(1+1/4) (sqrt3/2) = sqrt15/4