Help plz.!! Given that y=ex2, find dydx Hence find xex2dx?

1 Answer
Mar 27, 2018

Use the chain rule to find dydx.

dydx=(2x)ex2

As for the chain rule, let u=x2. Then du=2xdx and dx=du2x.

I=12eudu

I=12eu+C

I=12ex2+C

Alternatively we could have said

I=12(2x)ex2dx

I=12ex2+C (because integration is the opposite of differentiation)

This is the same answer we got using the substitution.

Hopefully this helps!