How can we prove that the value of 0!=1 ?

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Answer 1 · 2017-07-13T05:59:49

See below.

$n! =n(n-1)(n-2)(n-3) .... 2*1$

$:. n! = n*(n-1)!$

So long as $n!=0$ we can divide both sides by $n$

$:. (n!)/n = (n-1)!$

Now set $n=1$

$(1!)/1 =0!$

$:.0! = 1/1 =1$